Python: Check if a File or Directory Exists
There are quite a few ways to solve a problem in programming, and this holds true especially in Python. Many times you’ll find that multiple built-in or standard modules serve essentially the same purpose, but with slightly varying functionality. Checking if a file or directory exists using Python is definitely one of those cases.
Here are a few ways to check for existing files/directories and their nuances. Throughout these examples we’ll assume our current working directory has these files and directories in it:
drwxr-xr-x 3 scott staff 102 Jan 12 10:01 dir
-rw-r--r-- 1 scott staff 5 Jan 12 09:56 file.txt
lrwxr-xr-x 1 scott staff 8 Jan 12 09:56 link.txt -> file.txt
lrwxr-xr-x 1 scott staff 3 Jan 12 10:00 sym -> dir
Notice that we have one directory (dir
), one file (file.txt
), one file symlink (link.txt
), and one directory symlink (sym
).
Checking if a File Exists
This is arguably the easiest way to check if both a file exists and if it is a file.
import os
os.path.isfile('./file.txt') # True
os.path.isfile('./link.txt') # True
os.path.isfile('./fake.txt') # False
os.path.isfile('./dir') # False
os.path.isfile('./sym') # False
os.path.isfile('./foo') # False
Note that os.path.isfile
does follow symlinks, so we get True
when checking link.txt
.
isfile
is actually just a helper method that internally uses os.stat
and stat.S_ISREG(mode)
underneath, which we’ll touch on later.
Checking if a Directory Exists
Like the isfile
method, os.path.isdir
is the easiest way to check if a directory exists, or if the path given is a directory.
import os
os.path.isdir('./file.txt') # False
os.path.isdir('./link.txt') # False
os.path.isdir('./fake.txt') # False
os.path.isdir('./dir') # True
os.path.isdir('./sym') # True
os.path.isdir('./foo') # False
Again, just like isfile
, os.path.isdir
does follow symlinks. It is also just a simple wrapper around os.stat
and stat.S_ISDIR(mode)
, so you’re not getting much more than convenience from it.
Checking if Either Exist
Another way to check if a path exists (as long as you don’t care if the path points to a file or directory) is to use os.path.exists
.
import os
os.path.exists('./file.txt') # True
os.path.exists('./link.txt') # True
os.path.exists('./fake.txt') # False
os.path.exists('./dir') # True
os.path.exists('./sym') # True
os.path.exists('./foo') # False
As you can see, it doesn’t care if the path points to a file, directory, or symlink, so it’s almost like you’re using isfile(path) or isdir(path)
. But actually, internally it is just trying to call os.stat(path)
, and if an error is thrown then it returns False
.
Advanced
Throughout the article I’ve been mentioning how all of the above methods utilize the os.stat
method, so I figured it would be useful to take a look at it. This is a lower-level method that will provide you with detailed information about files, directories, sockets, buffers, and more.
Like all the other methods we’v already covered, os.stat
follows symlinks, so if you want to get the stat info on a link, try using os.lstat()
instead.
Since every operating system is different, the data provided by os.stat
varies greatly. Here is just some of the data that each OS has in common:
st_mode
: protection bitsst_uid
: owner’s user idst_gid
: owner’s group idst_size
: size of file in bytesst_atime
: time of last accessst_mtime
: time of last modificationst_ctime
: time of last metadata change on Unix, or time of creation on Windows
You can then use this data with the stat
module to get interesting information, like whether a path points to a socket (stat.S_ISSOCK(mode)
), or if a file is actually a named pipe (stat.S_ISFIFO(mode)
).
If you need some more advanced functionality, then this is where you should go. But for 90% of the time you’re dealing with directories and files, the os
or os.path
modules should have you covered.
Although, one valid use-case might be when you’re doing multiple tests on the same file and want to avoid the overhead of the stat system call for each test. So if you have quite a few tests to do then this will help you do it more efficiently.