Random Numbers

Finds the square of an specific number

Pysquare-Finder

finds the square root of an specific number using vanilla python

Calculations

To get the square root of a not exact number you need to do:
(X + Y) / √(Y) * 2
Example:
To get the square root of √(634): <- not exact

  1. get the radicand of √(634), add the radicand of the closest exact square root (625)
  2. divide by the square root of the closest exact square root and multiply by two
    You should have something like: 

634 + 625
--------- = 25.18
 25 * 2

Note

The code isnt 100% clean! It have a specific bug that: